2(x+1)=5[x-(3-x)]

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Solution for 2(x+1)=5[x-(3-x)] equation:


Simplifying
2(x + 1) = 5[x + -1(3 + -1x)]

Reorder the terms:
2(1 + x) = 5[x + -1(3 + -1x)]
(1 * 2 + x * 2) = 5[x + -1(3 + -1x)]
(2 + 2x) = 5[x + -1(3 + -1x)]
2 + 2x = 5[x + (3 * -1 + -1x * -1)]
2 + 2x = 5[x + (-3 + 1x)]

Reorder the terms:
2 + 2x = 5[-3 + x + 1x]

Combine like terms: x + 1x = 2x
2 + 2x = 5[-3 + 2x]
2 + 2x = [-3 * 5 + 2x * 5]
2 + 2x = [-15 + 10x]

Solving
2 + 2x = -15 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10x' to each side of the equation.
2 + 2x + -10x = -15 + 10x + -10x

Combine like terms: 2x + -10x = -8x
2 + -8x = -15 + 10x + -10x

Combine like terms: 10x + -10x = 0
2 + -8x = -15 + 0
2 + -8x = -15

Add '-2' to each side of the equation.
2 + -2 + -8x = -15 + -2

Combine like terms: 2 + -2 = 0
0 + -8x = -15 + -2
-8x = -15 + -2

Combine like terms: -15 + -2 = -17
-8x = -17

Divide each side by '-8'.
x = 2.125

Simplifying
x = 2.125

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